If we start with two charged quark hexagons, the third hexagon in the lattice could
become a $(b,c,s)$ triplet.
Recall that
the phase for the $(b,c,s)$ triplet is $18/27$, three times the charged lepton phase. The phase for a
charged triplet is $2/27$ or $4/27$. Three hexagon tiles form the core of a
honeycomb dual to a four qutrit extended tetractys. Note that the outer polygons here are rather asymmetrical. An alternative uses three charged triplets, including one non standard configuration:
This choice maintains (charge) triality on the trivalent subdiagrams.
Recall that the phase for the $(b,c,s)$ triplet is $18/27$, three times the charged lepton phase. The phase for a charged triplet is $2/27$ or $4/27$. Three hexagon tiles form the core of a honeycomb dual to a four qutrit extended tetractys. Note that the outer polygons here are rather asymmetrical. An alternative uses three charged triplets, including one non standard configuration:
This choice maintains (charge) triality on the trivalent subdiagrams.
The hexagon diagram was filched from an old post on graphene, where we noted the appearance of a universal $1/ 4 \pi$ factor, associated to the dark sector. How exciting that dark matter is something we can engineer!
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