Recall that the canonical form of the tribimaximal mixing matrix $T$ was in terms of $3 \times 3$ block magic matrices, with parameters $(1,\sqrt{2})$, where the $\sqrt{2}$ is the same as the $r$ parameter from the Koide formula. Forgetting the Koide formula for now, we may apply the $T$ transform to the basic permutation underlying an electroweak state,

to obtain a magic sum of a real $1$-circulant and imaginary $2$-circulant, namely which has a row sum of zero for the imaginary part and a normalisation choice of $6$ for the real part. Since mixing sends electroweak states to mass states, this matrix should contain information about the fundamental mass states. Observe that an application of $T$ to a boson diagonal results in a multiple of the identity matrix. The addition of a $\theta_{13}$ factor would perturb the resulting magic forms slightly, so that the real diagonal was no longer zero. With the tribimaximal ansatz, however, the real part of $\Lambda$ is a sum of left handed and right handed braids, as required.

6 years ago

Superluminal Neutrinos

ReplyDeletehttp://mathbin.net/74445

All right, thanks, number 26, but the explanations are lacking, no?

ReplyDeleteThe neutrino overlighting are an effect of neutrino interaction with extra dimensions, quantum whose distances are shorter than the distance for particles that do not violate CPT

ReplyDeleteThe non-zero angle theta13 would be like the angle of refraction of the vacuum with repect to the 2 different speeds, the speed of light particles are not involved in the CPT violation, responsible for the matter-antimatter asymmetry, and speed (length - curvature) of the particle conrrespondiente that violate CPT symmetry and responsible for the matter-antimatter

The violation of CPT directly involves the violation of a bounded quantum level, the Lorentz invariance. Is an effect that already includes the standard quantum theory. A particle has an amplitude to be outside the cone of light equal to:

exp-(r / lambda)

Where r is the particle excursion length and wavelength lamba associated with the particle

\

\ lambda = \ frac {\ hbar} {m \ cdot c}

\

Moreover, the experiments should show tau neutrino for a violation bounded similar to muon neutrinos. The certificate is due implicitly quantified the effect of space-time-energy

3 lengths in principle be quantified minimum space-time

The length corresponding to particles that do not violate CPT:

\

r (\ alpha ^ {-1}) = \ Biggles (\ frac {\ alpha ^ {-1}} {4 \ cdot \ pi} \ biggr) ^ {\ frac {1} {2}}

\

Alpha is the electromagnetic fine structure constant

2 lengths for the two radii of a bull in 7 dimensions, dimensions compactified Kaluza-Klein

\

L_ {p} (7D) = \ Biggles (\ frac {2 \ cdot (2 \ cdot \ pi) ^ {7}} {V_ {T} (7D)} \ biggr) ^ {\ frac {1} {7 +2}}

\

\

R_ {BH} (7D) = \ Biggles (\ frac {4 \ cdot (2 \ cdot \ pi) ^ {7}} {(7 +1) \ cdot V_ {T} (7D)} \ biggr) ^ {\ frac {1} {7 +1}}

\

Number 26, that is the last time that I allow unformatted comments. Enough is enough. I already told you that dollar signs worked for latex here. Now that you have a blog, you should write lengthier explanations over there.

ReplyDeleteThis is the final expression that explains the OPERA experiment, MINOS, and the speed of neutrinos from supernova SN1987A

ReplyDeleteIf the energy of the muon neutrino beam is lower than 0.105 GeV (energy of the muon), then the neutrino beam has a lower speed of light, since In (E / Emuon) = 0, where E = Emuon

For this reason the supernova SN1987A neutrino with a jet with an energy of about 10 Mev, its speed is lower than that of light

In this expression correction terms appear due to Cherenkov radiation in a vacuum type

$\

\frac{V(v\mu)-c}{c}=\frac{k\cdot\exp-\Biggl(\frac{r(\alpha^{-1})-R_{BH}(7D)}{r(\alpha^{-1})}\Biggr)^{-1}\cdot\ln\Biggl(\frac{E}{E\mu}\Biggr)}{\ln[\alpha^{-1}(m\mu)]\cdot\ln(\frac{m\tau}{me})}

\$

$V(v\mu)=speed\; muonic\; neutrinos$

$c=light\; speed$

$k=constant\approxeq\sqrt{30/8}$

$E\mu=muon\; energy\;(Gev)$

$E=energy\; nuonic\; neutrinos\;(Gev$

$\alpha^{-1}(m\mu)=electromagnetic\; coupling\; scale\; muon\; mass$

$m\tau=tau\; mass$

$me=electron\; mass$

If the equations are:

Superluminals neutrinos (quantum Lorentz violation limited)

http://mathbin.net/74445

Sigh. You need two dollar signs, number 26, one at each end. Anyway, like I said, you should just provide a link to your blog. That is all.

ReplyDeleteOk, thanks two dollars.

ReplyDeleteI am not disturb to any more, thanks very nucho sorry

In every site to write equations, formulas vary, sorry

Yes, one does need to figure out the local latex conventions, unfortunately, but this should not be difficult. And once you have your own setup, off you go.

ReplyDelete