## Wednesday, December 14, 2011

### A Four Color SM Higgs

Yesterday, Mitchell mentioned a Higgs mass formula by Dharwadker et al, based on the four colour theorem. This formula correctly predicted the Higgs mass. It is

$m_{H} = \frac{1}{2} (m_{W^{+}} + m_{W^{-}} + m_{Z})$

I'm not yet sure what to make of this, but since it must come from the tetractys diagonal, it suggests something like a degenerate boson Koide triplet $(W^{+}, W^{-}, Z)$. On taking the twisted Fourier dual, this is a $(e^{+}, e^{-}, \nu_{R})$ triplet. Note that it includes no generation multiplicity, but it seems to be about quark lepton mixing. If we include mirror states, we could interpret this triplet as $(e^{+}, e^{-}, \gamma)$, a basic annihilation triplet.

Recall that there are three ways to obtain each of these bosons via composition of $Z$ color states. Thus the boson triplet comes from three copies of the $Z$ color triplet.

I am beginning to be quite convinced by all these coincidences ... and not particularly by the $3$ sigma evidence itself, lol.