Now it may be that all of $V$, $E$ and $F$ are divisible by $3$, as in the examples shown. A counterexample is the $\chi = 3$ tetrahedron, which has $4$ faces and $5$ vertices. Counting $\chi = 3$ is a ternary analogue of the $\chi = 2$ Poincare paradigm. For a polygon in the plane, the characteristic $V - E$ is usually zero, but this can now be amended to $1$.
15 years ago


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