Recall that the $2 \times 2$ Fourier operator $F_2$ is just the Hadamard gate. Observe that under the Jordan product, this is an inverse to our operator $Q$. Since we also allow complex matrix algebras, the Fourier operator is there to turn diagonals into circulants, as it does for the $3 \times 3$ ternary Koide mass matrices.
A child could understand quantum gravity. Perhaps the stringers should be sent back to kindergarten.
6 years ago