In particular, $8$ is not equal to $9$, much as there are two distinct ways to create the number $57$ from two $3 \times 3$ matrices. As every child knows, one cannot fit a square peg in a triangular hole.
14 years ago
Wednesday, January 19, 2011
Riemann Revisited
Marco Frasca brings up one of our favourite old subjects: the unsolved Riemann hypothesis! Quantum arithmetic is not commutative, because three qubits are not the same thing as two qutrits.
In particular, $8$ is not equal to $9$, much as there are two distinct ways to create the number $57$ from two $3 \times 3$ matrices. As every child knows, one cannot fit a square peg in a triangular hole.
In particular, $8$ is not equal to $9$, much as there are two distinct ways to create the number $57$ from two $3 \times 3$ matrices. As every child knows, one cannot fit a square peg in a triangular hole.
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