tag:blogger.com,1999:blog-7307840825023135484.post5889805968485978097..comments2023-04-16T03:44:23.949+12:00Comments on Arcadian Pseudofunctor: Special Theory UpdateKeahttp://www.blogger.com/profile/05652514294703722285noreply@blogger.comBlogger10125tag:blogger.com,1999:blog-7307840825023135484.post-81109442671859635582011-04-04T11:21:08.617+12:002011-04-04T11:21:08.617+12:00They undeleted one of Kea's comments on that p...They undeleted one of Kea's comments on that proof page. I'm going to see if I can understand the idea behind it. Perhaps there's a simple proof that makes the result easy to obtain.<br /><br />By the way, one of Kea's answers on the zeta function generalization is quite striking and should be linked here. I'm sure she's discussed it in a blog (which I have trouble keeping up with): http://math.stackexchange.com/questions/30409/<br /><br />Now as to getting more rep points on SE, it should be noted that every time you make an edit on a post it brings it to the top of the question list and so exposes it to more people who might vote it up. However, after something like 5 or 10 edits, it becomes "community wiki" and no further reputation points accrue.CarlBrannenhttps://www.blogger.com/profile/17180079098492232258noreply@blogger.comtag:blogger.com,1999:blog-7307840825023135484.post-10277350825525654712011-04-03T17:22:20.058+12:002011-04-03T17:22:20.058+12:00Cool, Mitchell! Thanks. Yes, you are probably righ...Cool, Mitchell! Thanks. Yes, you are probably right about the theorem. Anyway, I answered 2 questions on the exchange, and now have commenting rights. But there is no action there now!Keahttps://www.blogger.com/profile/05652514294703722285noreply@blogger.comtag:blogger.com,1999:blog-7307840825023135484.post-18572434689335264692011-04-03T15:09:47.079+12:002011-04-03T15:09:47.079+12:00I did see your first deleted comment (not the seco...I did see your first deleted comment (not the second) where you said there might not be a simpler proof, because these matrices have a motivic origin. I think that's pretty unlikely. It's like saying you need schemes to prove Pythagoras's theorem, because 3^2 + 4^2 = 5^2, 3 and 5 are prime, and primes are associated to knots by Spec Z. What's more likely is that such theorems are trivial instances of the more profound relationships. Anyway, <a href="http://arxiv.org/abs/0809.1584" rel="nofollow">here's a proof of the Clifford torus theorem</a> due to Dmitry Tamarkin.Mitchellhttps://www.blogger.com/profile/10768655514143252049noreply@blogger.comtag:blogger.com,1999:blog-7307840825023135484.post-88384054098206850442011-04-02T06:51:03.301+13:002011-04-02T06:51:03.301+13:00Sounds simple, yes, but I am not familiar with the...Sounds simple, yes, but I am not familiar with the details of the Floer homology, which I suspect is not quite that simple.Keahttps://www.blogger.com/profile/05652514294703722285noreply@blogger.comtag:blogger.com,1999:blog-7307840825023135484.post-42539304836090931902011-04-02T00:07:42.628+13:002011-04-02T00:07:42.628+13:00OK, well, maybe we can have the discussion you wan...OK, well, maybe we can have the discussion you wanted here. The proof doesn't look complicated. The unitary mapping between MUBs defines a Hamiltonian flow, a Clifford torus moved by a Hamiltonian flow always overlaps its initial position somewhere, and the existence of this overlap (for the Clifford torus in the projective space of rays in Hilbert space) guarantees the existence of the unbiased vector.Mitchellhttps://www.blogger.com/profile/10768655514143252049noreply@blogger.comtag:blogger.com,1999:blog-7307840825023135484.post-63925174018702025282011-04-01T17:54:49.144+13:002011-04-01T17:54:49.144+13:00It's not really a "convention". Stac...It's not really a "convention". Stack Exchange is a privately owned company that quite strictly enforces how its website is used. The stupid feature is that they won't let you post comments until after your reputation reaches a certain level.<br /><br />The whole thing was originally designed for computer programmers asking how to fix bugs and write code. It probably made sense in that context but they've had their share of difficulty getting the mathematical community to adapt. The physics community seems to get along with it. That could be because the physics sample size is smaller or it could be because physicists are bosons and don't mind all doing the same thing.CarlBrannenhttps://www.blogger.com/profile/17180079098492232258noreply@blogger.comtag:blogger.com,1999:blog-7307840825023135484.post-56642050681277928482011-04-01T07:19:12.728+13:002011-04-01T07:19:12.728+13:00Yeah, OK, Mitchell, I get it but I just don't ...Yeah, OK, Mitchell, I get it but I just don't care.Keahttps://www.blogger.com/profile/05652514294703722285noreply@blogger.comtag:blogger.com,1999:blog-7307840825023135484.post-44414046577184468552011-03-31T20:01:37.757+13:002011-03-31T20:01:37.757+13:00Did you see Carl's instructions about how to g...Did you see Carl's instructions about how to get enough reputation points to leave a comment under an answer? At the moment you are posting discussion comments as whole new answers, but the Stack Exchange convention is that discussion occurs in the comment section of the answer being discussed.Mitchellhttps://www.blogger.com/profile/10768655514143252049noreply@blogger.comtag:blogger.com,1999:blog-7307840825023135484.post-83733517643889257432011-03-31T19:04:39.215+13:002011-03-31T19:04:39.215+13:00Ah, so my 2 short comments there were deleted, it ...Ah, so my 2 short comments there were deleted, it seems. Well, don't expect me to participate then.Keahttps://www.blogger.com/profile/05652514294703722285noreply@blogger.comtag:blogger.com,1999:blog-7307840825023135484.post-73261787664161362542011-03-31T18:07:22.870+13:002011-03-31T18:07:22.870+13:00Nice quote from the wikipedia article: The symplec...Nice quote from the <a href="http://en.wikipedia.org/wiki/Floer_homology" rel="nofollow">wikipedia</a> article: <i>The symplectic version of Floer homology figures in a crucial way in the formulation of the homological mirror symmetry conjecture.</i>Keahttps://www.blogger.com/profile/05652514294703722285noreply@blogger.com